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NEET 2001 (AIPMT) · Conservation of Energy

Conservation of Energy question from NEET 2001 (AIPMT)

Q43NEET 2001 · AIPMTEasy

Conservation of Energy

A child is sitting on a swing. Its minimum and maximum heights from the ground 0.75 m and 2 m respectively, its maximum speed will be

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Answer: (b)

  1. Maximum speed at the lowest point: 12mv2=mg(hmax−hmin)\frac{1}{2}mv^2 = mg(h_{max} - h_{min}).
  2. Δh=2−0.75=1.25 m\Delta h = 2 - 0.75 = 1.25\text{ m}
  3. v=2×10×1.25=25=5 m/sv = \sqrt{2 \times 10 \times 1.25} = \sqrt{25} = 5\text{ m/s}
  4. So the answer is (b) 5 m/s.
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