A child is sitting on a swing which performs S.H.M. It has minimum and maximum heights from ground 0.75 m and 2 m respectively. Its maximum speed will be [g = 10 ms²] (a) √(1.25) m/s (b) √(12.5) m/s (c) 5 m/s (d) 25 m/s

Answer: (c). Height difference between extreme and lowest position: h = 2 - 0.75 = 1.25 m. vmax = √(2gh) = √(2 × 10 × 1.25) = √(25). So the answer is (c) 5 m/s.

A child is sitting on a swing which performs S.H.M. It has minimum… | MHT CET 2021 (21 Sep, Shift 2)

Q65MHT CET 2021 · 21 SEP · SHIFT 2Medium

Simple Pendulum

A child is sitting on a swing which performs S.H.M. It has minimum and maximum heights from ground $0.75\text{ m}$ and $2\text{ m}$ respectively. Its maximum speed will be $\left[g = 10\,\frac{\text{m}}{\text{s}^{2}}\right]$

Show answer and solution

Answer: (c)

Height difference between extreme and lowest position: $h = 2 - 0.75 = 1.25\text{ m}$ .
$v_{max} = \sqrt{2gh} = \sqrt{2 \times 10 \times 1.25} = \sqrt{25}$ .
So the answer is (c) $5\text{ m/s}$ .

Report a mistake

Simple Pendulum question from MHT CET 2021 (21 Sep, Shift 2)

More questions on Simple Pendulum