A child of mass 5 kg is going round a merry-go-round that makes 1 rotation in 3.14 s. The radius of the merry-go-round is 2 m. The centrifugal force on the child will be (a) 50 N (b) 80 N (c) 100 N (d) 40 N

Answer: (d). ω = 2π/T = (2 × 3.14)/(3.14) = 2 rad/s Centrifugal force (in the rotating frame) = mω² r = 5 × 4 × 2 = 40 N So the answer is (d) 40 N.

A child of mass 5 kg is going round a merry-go-round that makes 1… | JEE Main 2023 (6 Apr, Shift 2)

Q20JEE Main 2023 · 6 APR · SHIFT 2Easy

Centripetal Acceleration & Force

A child of mass $5\text{ kg}$ is going round a merry-go-round that makes 1 rotation in $3.14\text{ s}$ . The radius of the merry-go-round is $2\text{ m}$ . The centrifugal force on the child will be

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Answer: (d)

$\omega = \frac{2\pi}{T} = \frac{2 \times 3.14}{3.14} = 2\text{ rad/s}$
Centrifugal force (in the rotating frame) $= m\omega^2 r = 5 \times 4 \times 2$
$= 40\text{ N}$
So the answer is (d) 40 N.

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