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MHT CET 2025 (21 Apr, Shift 1) · Apparent Weight & Lift

Apparent Weight & Lift question from MHT CET 2025 (21 Apr, Shift 1)

Q3MHT CET 2025 · 21 APR · SHIFT 1Medium

Apparent Weight & Lift

A child stands on a weighing machine inside a lift. When the lift is going down with acceleration g/3g/3, the machine shows a reading 20 N. When the lift goes upwards with acceleration g/3g/3, the reading would be ( g=g = gravitational acceleration)

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Answer: (a)

  1. Going down with g3\frac{g}{3}: m(g−g3)=2mg3=20⇒mg=30m\left(g - \frac{g}{3}\right) = \frac{2mg}{3} = 20 \Rightarrow mg = 30 N.
  2. Going up with g3\frac{g}{3}: m(g+g3)=4mg3=40m\left(g + \frac{g}{3}\right) = \frac{4mg}{3} = 40 N
  3. So the answer is (a) 40 N.
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