A child stands on the edge of the cliff 10 m above the ground and throws a stone horizontally with an initial speed of 5 m s⁻¹. Neglecting the air resistance, the speed with which the stone hits the ground will be ________ m s⁻¹ (given, g = 10 m s⁻²). (a) 20 (b) 25 (c) 30 (d) 15

Answer: (d). Horizontal: vx = 5 m/s stays constant. Vertical: vy² = 2gh = 2(10)(10) = 200 v = √(vx² + vy²) = √(25 + 200) = 15 m/s So the answer is (d) 15.

A child stands on the edge of the cliff 10 m above the ground and… | JEE Main 2023 (1 Feb, Shift 1)

Q4JEE Main 2023 · 1 FEB · SHIFT 1Easy

Horizontal Projectile & Inclined Plane

A child stands on the edge of the cliff $10\text{ m}$ above the ground and throws a stone horizontally with an initial speed of $5\text{ m s}^{-1}$ . Neglecting the air resistance, the speed with which the stone hits the ground will be ________ $\text{m s}^{-1}$ (given, $g = 10\text{ m s}^{-2}$ ).

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Answer: (d)

Horizontal: $v_x = 5\text{ m/s}$ stays constant.
Vertical: $v_y^2 = 2gh = 2(10)(10) = 200$
$v = \sqrt{v_x^2 + v_y^2} = \sqrt{25 + 200} = 15\text{ m/s}$
So the answer is (d) 15.

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Horizontal Projectile & Inclined Plane question from JEE Main 2023 (1 Feb, Shift 1)

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