Junction Transistor question from JEE Main 2021 (27 Aug, Shift 1)

Answer: 5

1. Diodes $D_1$, $D_2$ have anodes at the base-side node and cathodes at ground, and the 5 V cell drives current into that node through $R$, so both diodes are forward biased.
2. The node is clamped to about 0 V (ideal diodes), so the base gets no forward bias and the transistor is cut off.
3. With $I_C = 0$ there is no drop across the collector resistor: $V_0 = 5 - I_C R = 5\ \text{V}$
4. So $V_0 = 5$ V.