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MHT CET 2023 (11 May, Shift 2) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from MHT CET 2023 (11 May, Shift 2)

Q48MHT CET 2023 · 11 MAY · SHIFT 2Easy

Biot-Savart Law & Circular Coils

A circular arc of radius ' $r$ ' carrying current ' $I$ ' subtends an angle $\frac{\pi}{16}$ at its centre. The radius of a metal wire is uniform. The magnetic induction at the centre of circular arc is $[\mu_0 =$ permeability of free space]

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Answer: (c)

Arc of angle $\theta$ : $B = \frac{\mu_0 I\theta}{4\pi r}$ .
$\theta = \frac{\pi}{16}$ : $B = \frac{\mu_0 I}{4\pi r}\cdot\frac{\pi}{16} = \frac{\mu_0 I}{64r}$
So the answer is (c).

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