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MHT CET 2024 (10 May, Shift 1) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from MHT CET 2024 (10 May, Shift 1)

Q36MHT CET 2024 · 10 MAY · SHIFT 1Easy

Biot-Savart Law & Circular Coils

A circular arc of radius r carrying current ' I ' subtends an angle $\frac{\pi}{8}$ at its centre. The radius of a metal wire is uniform. The magnetic induction at the centre of circular arc is ( $\mu_0 =$ permeability of free space)

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Answer: (b)

Arc of angle $\theta$ : $B = \frac{\mu_0 I\theta}{4\pi r}$ .
$\theta = \frac{\pi}{8}$ : $B = \frac{\mu_0 I}{4\pi r}\cdot\frac{\pi}{8} = \frac{\mu_0 I}{32r}$
So the answer is (b).

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