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MHT CET 2026 (20 Apr, Shift 2) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from MHT CET 2026 (20 Apr, Shift 2)

Q6MHT CET 2026 · 20 APR · SHIFT 2Easy

Biot-Savart Law & Circular Coils

A circular arc of wire of radius of curvature $r$ subtends an angle of $\frac{\pi}{5}$ radian at its centre. If current $i$ is flowing in it then the magnetic induction at its centre is ( $\mu_0$ = permeability of free space)

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Answer: (d)

Arc of angle $\theta$ : $B = \frac{\mu_0 i\theta}{4\pi r}$ .
$\theta = \frac{\pi}{5}$ : $B = \frac{\mu_0 i}{4\pi r}\cdot\frac{\pi}{5} = \frac{\mu_0 i}{20r}$
So the answer is (d).

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