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Force on Current-Carrying Conductors question from NEET 2013

Q58NEET 2013Easy

Force on Current-Carrying Conductors

A circular coil ABCD carrying a current 'i' is placed in a uniform magnetic field. If the magnetic force on the segment AB is F⃗\vec{F}, the force on the remaining segment BCDA is

Figure

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Answer: (a)

  1. The net magnetic force on any closed current loop in a uniform field is zero.
  2. F⃗AB+F⃗BCDA=0⇒F⃗BCDA=−F⃗\vec{F}_{AB} + \vec{F}_{BCDA} = 0 \Rightarrow \vec{F}_{BCDA} = -\vec{F}
  3. So the answer is (a) −F⃗-\vec{F}.
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