A circular disc of radius 0.2 meter is placed in a uniform magnetic field of induction 1/π(Wbm²) in such a way that its axis makes an angle of 60° with B. The magnetic flux linked with the disc is (a) 0.08 Wb (b) 0.01 Wb (c) 0.02 Wb (d) 0.06 Wb

Answer: (c). Φ = BAcos θ with θ = 60° between B and the disc's axis. A = π(0.2)² = 0.04π m ² Φ = 1/π× 0.04π× 0.5 = 0.02 Wb So the answer is (c) 0.02 Wb.

A circular disc of radius 0.2 meter is placed in a uniform magnetic… | NEET 2008 (AIPMT)

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Magnetic Flux & Faraday's Law

A circular disc of radius 0.2 meter is placed in a uniform magnetic field of induction $\frac{1}{\pi}\left(\frac{\text{Wb}}{\text{m}^{2}}\right)$ in such a way that its axis makes an angle of 60° with $\vec{B}.$ The magnetic flux linked with the disc is

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Answer: (c)

$\Phi = BA\cos\theta$ with $\theta = 60^\circ$ between $\vec{B}$ and the disc's axis.
$A = \pi(0.2)^{2} = 0.04\pi$ m $^{2}$
$\Phi = \frac{1}{\pi}\times 0.04\pi\times 0.5 = 0.02$ Wb
So the answer is (c) 0.02 Wb.

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