A circular disc of radius 20 cm is placed in uniform magnetic field of induction 7/22 Wb/m ² in such a way that its axis makes an angle of 60° with B. The magnetic flux linked with the disc is (cos 60° = 0.5) (a) 0.01 Wb (b) 0.02 Wb (c) 0.06 Wb (d) 0.08 Wb

Answer: (b). Flux Φ = BAcos θ, where θ is the angle between B and the axis (normal) of the disc. A = π r² = 22/7(0.2)² = 22/7× 0.04 m ² Φ = 7/22×22/7× 0.04× 0.5 = 0.02 Wb So the answer is (b) 0.02 Wb.

A circular disc of radius 20 cm is placed in uniform magnetic field… | MHT CET 2026 (20 Apr, Shift 2)

Q1MHT CET 2026 · 20 APR · SHIFT 2Easy

Magnetic Flux & Faraday's Law

A circular disc of radius 20 cm is placed in uniform magnetic field of induction $\frac{7}{22}$ Wb/m $^{2}$ in such a way that its axis makes an angle of $60^\circ$ with $\vec{B}$ . The magnetic flux linked with the disc is $(\cos 60^\circ = 0.5)$

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Answer: (b)

Flux $\Phi = BA\cos\theta$ , where $\theta$ is the angle between $\vec{B}$ and the axis (normal) of the disc.
$A = \pi r^{2} = \frac{22}{7}(0.2)^{2} = \frac{22}{7}\times 0.04$ m $^{2}$
$\Phi = \frac{7}{22}\times\frac{22}{7}\times 0.04\times 0.5 = 0.02$ Wb
So the answer is (b) $0.02$ Wb.

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Magnetic Flux & Faraday's Law question from MHT CET 2026 (20 Apr, Shift 2)

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