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MHT CET 2026 (15 May, Shift 2) · Rolling Motion

Rolling Motion question from MHT CET 2026 (15 May, Shift 2)

Q3MHT CET 2026 · 15 MAY · SHIFT 2Medium

Rolling Motion

A circular ring and a solid sphere having same radius roll down on an inclined plane from rest without slipping. The ratio of their velocities when reached at the bottom of the plane $\sqrt{\frac{x}{5}}$ where the value of $x$ is

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Answer: (b)

Rolling from height $h$ : $v^2 = \dfrac{2gh}{1 + k^2/R^2}$ .
Ring: $v_r^2 = gh$ ; solid sphere: $v_s^2 = \frac{10}{7}gh$ .
$\dfrac{v_r}{v_s} = \sqrt{\dfrac{7}{10}} = \sqrt{\dfrac{3.5}{5}}$
So $x = 3.5$ : answer (b).

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