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NEET 2008 (AIPMT) · Force on Current-Carrying Conductors

Force on Current-Carrying Conductors question from NEET 2008 (AIPMT)

Q65NEET 2008 · AIPMTEasy

Force on Current-Carrying Conductors

A closed loop PQRS carrying a current is placed in a uniform magnetic field. If the magnetic forces on segments PS, SR and RQ are F1, F2 and F3 respectively and are in the plane of the paper and along the directions shown, the force on the segment QP is

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Answer: (d)

Net force on a closed loop in a uniform field is zero.
Sum of the three given forces: $(F_3 - F_1)$ horizontally and $F_2$ downward.
Force on QP balances them: $F_{QP} = \sqrt{(F_3 - F_1)^2 + F_2^2}$
So the answer is (d).

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