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JEE Main 2024 (27 Jan, Shift 2) · Beats

Beats question from JEE Main 2024 (27 Jan, Shift 2)

Q38JEE Main 2024 · 27 JAN · SHIFT 2Medium

Beats

A closed organ pipe 150 cm150\text{ cm} long gives 7 beats per second with an open organ pipe of length 350 cm350\text{ cm}, both vibrating in fundamental mode. The velocity of sound is __________ m/s\text{m/s}.

Numerical answer type. Work it out, then open the answer.

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Answer: 294

  1. Closed pipe: fc=v4×1.5=v6f_c = \frac{v}{4 \times 1.5} = \frac{v}{6}; open pipe: fo=v2×3.5=v7f_o = \frac{v}{2 \times 3.5} = \frac{v}{7}.
  2. Beats: v6−v7=v42=7\frac{v}{6} - \frac{v}{7} = \frac{v}{42} = 7
  3. v=294v = 294 m/s
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