A closed pipe containing liquid showed a pressure P₁ by gauge. When the valve was opened, pressure was reduced to P₂. The speed of water flowing out of the pipe is ( ρ =density of water) (a) [((P₁ - P₂))/(ρ)]1/2 (b) [(2(P₁ - P₂))/(ρ)]1/2 (c) [((P₂ - P₁))/(ρ)]1/2 (d) [(2(P₂ - P₁))/(ρ)]1/2

Answer: (b). Closed valve: v = 0, pressure P₁. Open valve: pressure P₂, speed v. Bernoulli: P₁ = P₂ + 1/2ρ v² v = [(2(P₁ - P₂))/(ρ)]1/2 So the answer is (b).

A closed pipe containing liquid showed a pressure P₁ by gauge. When… | MHT CET 2026 (16 Apr, Shift 1)

Q3MHT CET 2026 · 16 APR · SHIFT 1Medium

Bernoulli's Equation

A closed pipe containing liquid showed a pressure $P_1$ by gauge. When the valve was opened, pressure was reduced to $P_2$ . The speed of water flowing out of the pipe is ( $\rho$ =density of water)

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Answer: (b)

Closed valve: $v = 0$ , pressure $P_1$ . Open valve: pressure $P_2$ , speed $v$ .
Bernoulli: $P_1 = P_2 + \frac{1}{2}\rho v^2$
$v = \left[\dfrac{2(P_1 - P_2)}{\rho}\right]^{1/2}$
So the answer is (b).

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Bernoulli's Equation question from MHT CET 2026 (16 Apr, Shift 1)

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