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NEET 2022 (Phase 2) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from NEET 2022 (Phase 2)

Q67NEET 2022 · PHASE 2Easy

Biot-Savart Law & Circular Coils

A closely packed coil having 1000 turns has an average radius of 62.8 cm. If current carried by the wire of the coil is 1 A, the value of magnetic field produced at the centre of the coil will be (permeability of free space =4π×10−7= 4\pi \times 10^{-7} H/m) nearly

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Answer: (a)

  1. B=μ0nI2rB = \frac{\mu_0 n I}{2r}
  2. B=4π×10−7×1000×12×0.628=1.256×10−31.256B = \frac{4\pi\times10^{-7}\times 1000\times 1}{2\times 0.628} = \frac{1.256\times10^{-3}}{1.256}
  3. So the answer is (a) 10−3 T10^{-3}\text{ T}.
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