A coil having an inductance of 1/π H is connected in series with a resistance of 300 Ω. If A.C. Source (20 V - 200 Hz) is connected across the combination, the phase angle between voltage and current is (a) tan ⁻¹(3/4) (b) tan ⁻¹(4/3) (c) tan ⁻¹(5/4) (d) tan ⁻¹(4/5)

Answer: (b). tan φ = XL/R, with XL = 2π f L = 2π × 200 × 1/π = 400 Ω. tan φ = (400)/(300) = 4/3 So the answer is (b) tan ⁻¹(4/3).

A coil having an inductance of 1/π H is connected in series with a… | MHT CET 2022 (11 Aug, Shift 2)

Q37MHT CET 2022 · 11 AUG · SHIFT 2Easy

RL and RC Series Circuits

A coil having an inductance of $\frac{1}{\pi}\text{ H}$ is connected in series with a resistance of $300\ \Omega$ . If A.C. Source $(20\text{ V} - 200\text{ Hz})$ is connected across the combination, the phase angle between voltage and current is

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Answer: (b)

$\tan\phi = \frac{X_L}{R}$ , with $X_L = 2\pi f L = 2\pi \times 200 \times \frac{1}{\pi} = 400\ \Omega$ .
$\tan\phi = \frac{400}{300} = \frac{4}{3}$
So the answer is (b) $\tan^{-1}\left(\frac{4}{3}\right)$ .

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