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JEE Main 2004 (AIEEE) · Magnetic Flux & Faraday's Law

Magnetic Flux & Faraday's Law question from JEE Main 2004 (AIEEE)

Q85JEE Main 2004 · AIEEEEasy

Magnetic Flux & Faraday's Law

A coil having nn turns and resistance RΩR\Omega is connected with a galvanometer of resistance 4RΩ.4R\Omega. This combination is moved in time tt seconds from a magnetic field W1W_1 weber to W2W_2 weber. The induced current in the circuit is

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Answer: (b)

  1. Total resistance R+4R=5RR + 4R = 5R
  2. Faraday-Lenz: e=−n(W2−W1)te = -\frac{n(W_2 - W_1)}{t}
  3. I=e5R=−n(W2−W1)5RtI = \frac{e}{5R} = -\frac{n(W_2 - W_1)}{5Rt}
  4. So the answer is (b) −n(W2−W1)5Rt-\frac{n(W_2 - W_1)}{5Rt}.
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