A coil having ' N ' turns and resistance ' R ' Ω is connected to a galvanometer of resistance ' 6 R ' Ω. The magnetic flux linked with this coil changes from φ₁ weber to φ₂ weber in time ' t ' second. The induced current in the circuit is (a) (N(φ₂ - φ₁))/(t) (b) (N(φ₂ - φ₁))/(7Rt) (c) (N(φ₂ - φ₁))/(Rt) (d) (N(φ₂ - φ₁))/(6Rt)

Answer: (b). Total resistance R + 6R = 7R Emf e = (N(φ₂ - φ₁))/(t) (magnitude) I = e/7R = (N(φ₂ - φ₁))/(7Rt) So the answer is (b) (N(φ₂ - φ₁))/(7Rt).

A coil having ' N ' turns and resistance ' R ' Ω is connected to a… | MHT CET 2025 (5 May, Shift 2)

Q25MHT CET 2025 · 5 MAY · SHIFT 2Easy

Magnetic Flux & Faraday's Law

A coil having ' $N$ ' turns and resistance ' $R$ ' $\Omega$ is connected to a galvanometer of resistance ' 6 R ' $\Omega$ . The magnetic flux linked with this coil changes from $\phi_1$ weber to $\phi_2$ weber in time ' t ' second. The induced current in the circuit is

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Answer: (b)

Total resistance $R + 6R = 7R$
Emf $e = \frac{N(\phi_2 - \phi_1)}{t}$ (magnitude)
$I = \frac{e}{7R} = \frac{N(\phi_2 - \phi_1)}{7Rt}$
So the answer is (b) $\frac{N(\phi_2 - \phi_1)}{7Rt}$ .

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Magnetic Flux & Faraday's Law question from MHT CET 2025 (5 May, Shift 2)

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