A coil having 'n' turns and resistance 'R' is connected with a galvanometer of resistance '2R'. This combination is moved in time 't' from flux φ₁ to φ₂ Wb. The induced current in the circuit is (a) (n(φ₁ - φ₂))/(Rt) (b) (n(φ₂ - φ₁))/(Rt) (c) (n(φ₂ - φ₁))/(3Rt) (d) (n(φ₂ - φ₁))/(2Rt)

Answer: (c). Total resistance R + 2R = 3R Emf magnitude e = (n(φ₂ - φ₁))/(t) I = e/3R = (n(φ₂ - φ₁))/(3Rt) (in magnitude) So the answer is (c) (n(φ₂ - φ₁))/(3Rt).

A coil having 'n' turns and resistance 'R' is connected with a… | MHT CET 2026 (11 Apr, Shift 2)

Q8MHT CET 2026 · 11 APR · SHIFT 2Easy

Magnetic Flux & Faraday's Law

A coil having 'n' turns and resistance 'R' is connected with a galvanometer of resistance '2R'. This combination is moved in time 't' from flux $\phi_1$ to $\phi_2$ Wb. The induced current in the circuit is

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Answer: (c)

Total resistance $R + 2R = 3R$
Emf magnitude $e = \frac{n(\phi_2 - \phi_1)}{t}$
$I = \frac{e}{3R} = \frac{n(\phi_2 - \phi_1)}{3Rt}$ (in magnitude)
So the answer is (c) $\frac{n(\phi_2 - \phi_1)}{3Rt}$ .

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Magnetic Flux & Faraday's Law question from MHT CET 2026 (11 Apr, Shift 2)

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