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JEE Main 2018 (16 Apr, Shift 1) · Rotating Conductors & AC Generator

Rotating Conductors & AC Generator question from JEE Main 2018 (16 Apr, Shift 1)

Q31JEE Main 2018 · 16 APR · SHIFT 1Easy

Rotating Conductors & AC Generator

A coil of cross-sectional area A having n turns is placed in a uniform magnetic field B. When it is rotated with an angular velocity $\omega,$ the maxium e.m.f. induced in the coil will be:

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Answer: (c)

Flux through the coil: $\phi = nBA\cos\omega t$ .
Induced emf: $e = -\frac{d\phi}{dt} = nBA\omega\sin\omega t$ .
Maximum when $\sin\omega t = 1$ : $e_0 = nBA\omega$ .
So the answer is (c) $nBA\omega$ .

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