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JEE Main 2022 (29 Jul, Shift 1) · Inductors & DC Transients (Mixed)

Inductors & DC Transients (Mixed) question from JEE Main 2022 (29 Jul, Shift 1)

Q7JEE Main 2022 · 29 JUL · SHIFT 1Easy

Inductors & DC Transients (Mixed)

A coil of inductance 1 H and resistance 100 Ω100\ \Omega is connected to a battery of 6 V. Determine approximately:

(a) The time elapsed before the current acquires half of its steady - state value.

(b) The energy stored in the magnetic field associated with the coil at an instant 15 ms after the circuit is switched on. (Given ln⁡2=0.693, e−3/2=0.25\ln 2 = 0.693,\ e^{-3/2} = 0.25)

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Answer: (c)

  1. τ=LR=1100=10 ms\tau = \frac{L}{R} = \frac{1}{100} = 10\text{ ms}, i=i0(1−e−t/τ)i = i_0(1 - e^{-t/\tau}) with i0=6100=0.06 Ai_0 = \frac{6}{100} = 0.06\text{ A}.
  2. Half value: e−t/τ=12⇒t=τln⁡2=10×0.693≈7 mse^{-t/\tau} = \frac{1}{2} \Rightarrow t = \tau\ln 2 = 10 \times 0.693 \approx 7\text{ ms}
  3. At t=15 mst = 15\text{ ms}: i=0.06(1−e−3/2)=0.06×0.75=0.045 Ai = 0.06(1 - e^{-3/2}) = 0.06 \times 0.75 = 0.045\text{ A}
  4. U=12Li2=12(1)(0.045)2≈1×10−3 JU = \frac{1}{2}Li^2 = \frac{1}{2}(1)(0.045)^2 \approx 1\times10^{-3}\text{ J}
  5. So the answer is (c) t = 7 ms; U = 1 mJ.
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