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MHT CET 2025 (23 Apr, Shift 2) · Magnetic Flux & Faraday's Law

Magnetic Flux & Faraday's Law question from MHT CET 2025 (23 Apr, Shift 2)

Q31MHT CET 2025 · 23 APR · SHIFT 2Medium

Magnetic Flux & Faraday's Law

A coil of ' $n$ ' turns and area ' $A$ ' is suddenly removed from a magnetic field, a charge ' $q$ ' flows through the coil. If resistance of the coil is ' $R$ ' then the magnetic flux density is (in $\text{Wb/m}^{2}$ )

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Answer: (b)

Removing the coil: flux changes from $nBA$ to $0$ , so $\Delta\phi = nBA$ .
$q = \frac{\Delta\phi}{R} = \frac{nBA}{R}$
$B = \frac{qR}{nA}$
So the answer is (b) $\frac{qR}{nA}$ .

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