A coil of resistance 250 Ω is placed in a magnetic field. If the magnetic flux (φ) linked with the coil varies with time t(s) as φ = 50t² + 7. The current in the coil at t = 4 s is (a) 1.3 A (b) 1.4 A (c) 1.5 A (d) 1.6 A

Answer: (d). |e| = (dφ)/(dt) = 100t; at t = 4 s, |e| = 400 V I = e/R = (400)/(250) = 1.6 A So the answer is (d) 1.6 A.

A coil of resistance 250 Ω is placed in a magnetic field. If the… | MHT CET 2024 (16 May, Shift 1)

Q33MHT CET 2024 · 16 MAY · SHIFT 1Easy

Magnetic Flux & Faraday's Law

A coil of resistance $250\,\Omega$ is placed in a magnetic field. If the magnetic flux $(\phi)$ linked with the coil varies with time $t(\text{s})$ as $\phi = 50t^{2} + 7$ . The current in the coil at $t = 4\text{ s}$ is

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Answer: (d)

$|e| = \frac{d\phi}{dt} = 100t$ ; at $t = 4$ s, $|e| = 400$ V
$I = \frac{e}{R} = \frac{400}{250} = 1.6$ A
So the answer is (d) 1.6 A.

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