A coil of resistance 400 Ω is placed in a magnetic field. If the magnetic flux ' φ ' ( Wb) linked with the coil varies with time ' t ' ( s) is φ = 50t² + 4, the current in the coil at t = 2 s will be (a) 1 A (b) 2 A (c) 0.5 A (d) 0.1 A

Answer: (c). |e| = (dφ)/(dt) = 100t; at t = 2 s, |e| = 200 V I = e/R = (200)/(400) = 0.5 A So the answer is (c) 0.5 A.

A coil of resistance 400 Ω is placed in a magnetic field. If the… | MHT CET 2025 (22 Apr, Shift 1)

Q28MHT CET 2025 · 22 APR · SHIFT 1Easy

Magnetic Flux & Faraday's Law

A coil of resistance $400\,\Omega$ is placed in a magnetic field. If the magnetic flux ' $\phi$ ' ( Wb) linked with the coil varies with time ' $t$ ' ( $\text{s}$ ) is $\phi = 50t^{2} + 4$ , the current in the coil at $t = 2\text{ s}$ will be

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Answer: (c)

$|e| = \frac{d\phi}{dt} = 100t$ ; at $t = 2$ s, $|e| = 200$ V
$I = \frac{e}{R} = \frac{200}{400} = 0.5$ A
So the answer is (c) 0.5 A.

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