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NEET 2012 (AIPMT, Prelims) · Magnetic Flux & Faraday's Law

Magnetic Flux & Faraday's Law question from NEET 2012 (AIPMT, Prelims)

Q79NEET 2012 · AIPMT · PRELIMSEasy

Magnetic Flux & Faraday's Law

A coil of resistance 400 Ω\Omega is placed in a magnetic field. If the magnetic flux ϕ\phi (Wb) linked with the coil varies with time t (sec) as ϕ=50t2+4\phi = 50t^{2} + 4.

The current in the coil at t = 2 sec is

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Answer: (a)

  1. ∣e∣=dϕdt=100t|e| = \frac{d\phi}{dt} = 100t; at t=2t = 2 s, ∣e∣=200|e| = 200 V
  2. I=200400=0.5I = \frac{200}{400} = 0.5 A
  3. So the answer is (a) 0.5 A.
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