Physics Circle home Student Login

Home›Chapters›Electromagnetic Induction PYQs›Self-Inductance & Energy›Question 26

MHT CET 2025 (25 Apr, Shift 2) · Self-Inductance & Energy

Self-Inductance & Energy question from MHT CET 2025 (25 Apr, Shift 2)

Q26MHT CET 2025 · 25 APR · SHIFT 2Easy

Self-Inductance & Energy

A coil of wire of radius ' rr ' has 600 turns and a self-inductance of 108 mH. The self-inductance of a coil with same radius and 500 turns is

Show answer and solution

Answer: (b)

  1. Same radius: L∝N2L \propto N^2.
  2. L2=108×(500600)2=108×2536=75 mHL_2 = 108\times\left(\dfrac{500}{600}\right)^2 = 108\times\dfrac{25}{36} = 75\text{ mH}
  3. So the answer is (b) 75 mH.
Report a mistake

More questions on Self-Inductance & Energy