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MHT CET 2026 (13 May, Shift 2) · Self-Inductance & Energy

Self-Inductance & Energy question from MHT CET 2026 (13 May, Shift 2)

Q7MHT CET 2026 · 13 MAY · SHIFT 2Easy

Self-Inductance & Energy

A coil of wire of radius rr has 600600 turns and a self-inductance of 108108 mH. The self inductance of a coil with same radius and 500500 turns is

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Answer: (b)

  1. Same radius (same coil shape): L∝N2L \propto N^2.
  2. L2=108×(500600)2=108×2536L_2 = 108\times\left(\dfrac{500}{600}\right)^2 = 108\times\dfrac{25}{36}
  3. L2=75 mHL_2 = 75\text{ mH}
  4. So the answer is (b) 75 mH.
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