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JEE Main 2024 (31 Jan, Shift 1) · Level Road & Rotating Platform

Level Road & Rotating Platform question from JEE Main 2024 (31 Jan, Shift 1)

Q5JEE Main 2024 · 31 JAN · SHIFT 1Easy

Level Road & Rotating Platform

A coin is placed on a disc. The coefficient of friction between the coin and the disc is $\mu$ . If the distance of the coin from the center of the disc is $r$ , the maximum angular velocity which can be given to the disc, so that the coin does not slip away, is:

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Answer: (b)

Static friction provides the centripetal force: $m\omega^2 r \le \mu m g$ .
$\omega_{max} = \sqrt{\frac{\mu g}{r}}$
So the answer is (b).

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