A common emitter amplifier has a voltage gain of 50, an input impedance of 100 Ω and an output impedance of 200 Ω. The power gain of the amplifier is (a) 1000 (b) 1250 (c) 100 (d) 500

Answer: (b). AV = β(Ro)/(Ri) ⇒ β = (50 × 100)/(200) = 25 AP = β AV = 25 × 50 = 1250 So the answer is (b) 1250.

A common emitter amplifier has a voltage gain of 50, an input… | NEET 2007 (AIPMT)

Q114NEET 2007 · AIPMTEasy

Junction Transistor

A common emitter amplifier has a voltage gain of 50, an input impedance of $100\ \Omega$ and an output impedance of $200\ \Omega$ . The power gain of the amplifier is

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Answer: (b)

$A_V = \beta\frac{R_o}{R_i} \Rightarrow \beta = \frac{50 \times 100}{200} = 25$
$A_P = \beta A_V = 25 \times 50 = 1250$
So the answer is (b) 1250.

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