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MHT CET 2024 (10 May, Shift 1) · Velocity of Efflux (Torricelli)

Velocity of Efflux (Torricelli) question from MHT CET 2024 (10 May, Shift 1)

Q10MHT CET 2024 · 10 MAY · SHIFT 1Medium

Velocity of Efflux (Torricelli)

A completely filled water tank of height ' $h$ ' has a hole at the bottom. The total pressure of the bottom is 4 H and atmospheric pressure is H. The velocity of water flowing out of the hole is ( $\rho =$ density of water)

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Answer: (c)

Gauge pressure at the bottom: $\rho g h = 4H - H = 3H$
$\frac{1}{2}\rho v^2 = 3H \Rightarrow v = \sqrt{\frac{6H}{\rho}}$
So the answer is (c) $\sqrt{\frac{6H}{\rho}}$ .

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