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JEE Main 2022 (25 Jul, Shift 1) · Capacitance of a Conductor

Capacitance of a Conductor question from JEE Main 2022 (25 Jul, Shift 1)

Q11JEE Main 2022 · 25 JUL · SHIFT 1Easy

Capacitance of a Conductor

A condenser of 2 μF2\ \mu\text{F} capacitance is charged steadily from 0 to 5 C5\text{ C}. Which of the following graph represents correctly the variation of potential difference (V)(V) across it's plates with respect to the charge (Q)(Q) on the condenser?

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Answer: (a)

  1. V=QCV = \frac{Q}{C} with constant CC, so V∝QV \propto Q: a straight line through the origin.
  2. At Q=5 CQ = 5\text{ C}: V=52×10−6=2.5×106 VV = \frac{5}{2\times10^{-6}} = 2.5\times10^{6}\text{ V}.
  3. So the answer is (a), the straight line ending at 2.5×106 V2.5\times10^{6}\text{ V}.
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