A condenser of capacity ' C₁ ' is charged to potential ' V₁ ' and then disconnected. Uncharged capacitor of capacity ' C₂ ' is connected in parallel with ' C₁ '. The resultant potential ' V₂ ' is (a) (V₁ C₂)/(C₁) (b) (C₂)/(C₁ + C₂) (c) (C₁ V₁)/(C₂) (d) (C₁ V₁)/(C₁ + C₂)

Answer: (d). Charge is conserved: C₁V₁ = (C₁ + C₂)V₂. V₂ = (C₁V₁)/(C₁ + C₂) So the answer is (d).

A condenser of capacity ' C₁ ' is charged to potential ' V₁ ' and… | MHT CET 2021 (21 Sep, Shift 2)

Q22MHT CET 2021 · 21 SEP · SHIFT 2Easy

Charge Sharing & Loss of Energy

A condenser of capacity ' $C_1$ ' is charged to potential ' $V_1$ ' and then disconnected. Uncharged capacitor of capacity ' $C_2$ ' is connected in parallel with ' $C_1$ '. The resultant potential ' $V_2$ ' is

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Answer: (d)

Charge is conserved: $C_1V_1 = (C_1 + C_2)V_2$ .
$V_2 = \frac{C_1V_1}{C_1 + C_2}$
So the answer is (d).

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Charge Sharing & Loss of Energy question from MHT CET 2021 (21 Sep, Shift 2)

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