A condenser of capacity C₁ is charged to potential V₁ and then disconnected. Uncharged capacitor of capacity C₂ is connected in parallel with C₁. The resultant potential V₂ is (a) (C₁ V₁)/(C₂) (b) (C₁ V₁)/(C₁ + C₂) (c) (C₂ V₁)/(C₁) (d) (C₂ V₁)/(C₁ + C₂)

Answer: (b). Charge is conserved: C₁V₁ = (C₁ + C₂)V₂. V₂ = (C₁V₁)/(C₁ + C₂) So the answer is (b).

A condenser of capacity C₁ is charged to potential V₁ and then… | MHT CET 2026 (13 Apr, Shift 1)

Q2MHT CET 2026 · 13 APR · SHIFT 1Easy

Charge Sharing & Loss of Energy

A condenser of capacity $C_1$ is charged to potential $V_1$ and then disconnected. Uncharged capacitor of capacity $C_2$ is connected in parallel with $C_1$ . The resultant potential $V_2$ is

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Answer: (b)

Charge is conserved: $C_1V_1 = (C_1 + C_2)V_2$ .
$V_2 = \frac{C_1V_1}{C_1 + C_2}$
So the answer is (b).

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