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JEE Main 2025 (28 Jan, Shift 2) · Motional EMF

Motional EMF question from JEE Main 2025 (28 Jan, Shift 2)

Q16JEE Main 2025 · 28 JAN · SHIFT 2Medium

Motional EMF

Figure

A conducting bar moves on two conducting rails as shown in the figure. A constant magnetic field B exists into the page. The bar starts to move from the vertex at time t = 0 with a constant velocity. If the induced EMF is E ∝ tn, then value of n is _________.

Numerical answer type. Work it out, then open the answer.

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Answer: 1

  1. Bar starts at the vertex and moves up with constant vv, so its height is y=vty = vt.
  2. Length of bar between the rails l=2ytan⁡α∝tl = 2y\tan\alpha \propto t (α\alpha = half-angle of the V).
  3. E=Blv∝tE = Blv \propto t, so E∝t1E \propto t^1.
  4. So n=1n = 1.
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