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NEET 2009 (AIPMT) · Magnetic Flux & Faraday's Law

Magnetic Flux & Faraday's Law question from NEET 2009 (AIPMT)

Q82NEET 2009 · AIPMTMedium

Magnetic Flux & Faraday's Law

A conducting circular loop is placed in a uniform magnetic field 0.04 T with its plane perpendicular to the magnetic field. The radius of the loop starts shrinking at 2 mm/s. The induced emf in the loop when the radius is 2 cm is

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Answer: (d)

  1. e=B⋅2πrdrdte = B \cdot 2\pi r\frac{dr}{dt}
  2. e=0.04×2π×0.02×2×10−3e = 0.04 \times 2\pi \times 0.02 \times 2 \times 10^{-3}
  3. e=3.2π×10−6e = 3.2\pi \times 10^{-6} V
  4. So the answer is (d) 3.2π μ3.2\pi\ \muV.
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