A conducting ring of certain resistance is falling towards a current carrying straight long conductor. The ring and conductor are in the same plane. Then (a) induced current in the coil is zero. (b) induced current in the coil is anticlockwise. (c) induced current in the coil is clockwise. (d) ring will come to rest.

Answer: (c). Above a wire carrying current to the right, the field is out of the page. As the ring falls towards the wire, the field and hence the outward flux increase. The induced current must give an into-the-page field, so it is clockwise. So the answer is (c).

A conducting ring of certain resistance is falling towards a current… | MHT CET 2025 (21 Apr, Shift 2)

Q10MHT CET 2025 · 21 APR · SHIFT 2Medium

Lenz's Law, Eddy Currents & Induced Electric Field

A conducting ring of certain resistance is falling towards a current carrying straight long conductor. The ring and conductor are in the same plane. Then

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Answer: (c)

Above a wire carrying current to the right, the field is out of the page.
As the ring falls towards the wire, the field and hence the outward flux increase.
The induced current must give an into-the-page field, so it is clockwise.
So the answer is (c).

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Lenz's Law, Eddy Currents & Induced Electric Field question from MHT CET 2025 (21 Apr, Shift 2)

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