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MHT CET 2025 (20 Apr, Shift 1) · Electric Potential & Equipotentials

Electric Potential & Equipotentials question from MHT CET 2025 (20 Apr, Shift 1)

Q26MHT CET 2025 · 20 APR · SHIFT 1Easy

Electric Potential & Equipotentials

A conducting sphere of radius ' R ' is given a charge ' QQ ' uniformly. The electric field and the electric potential at the centre of the sphere are respectively [ ε0=\varepsilon_0 = permittivity of free space]

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Answer: (a)

  1. Inside a conductor in equilibrium E=0E = 0, so the field at the centre is zero.
  2. The whole conductor is equipotential: Vcentre=Vsurface=Q4πε0RV_{\text{centre}} = V_{\text{surface}} = \frac{Q}{4\pi\varepsilon_0 R}
  3. So the answer is (a) zero and Q4πε0R\frac{Q}{4\pi\varepsilon_0 R}.
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