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JEE Main 2017 (9 Apr, Shift 1) · Conical Pendulum & Funnel

Conical Pendulum & Funnel question from JEE Main 2017 (9 Apr, Shift 1)

Q16JEE Main 2017 · 9 APR · SHIFT 1Easy

Conical Pendulum & Funnel

A conical pendulum of length 1 m makes an angle θ\theta = 45o w.r.t. Z-axis and moves in a circle in the XY plane. The radius of the circle is 0.4 m and its center is vertically below O. The speed of the pendulum, in its circular path, will be: (Take g = 10 ms−2)

Figure

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Answer: (d)

  1. Conical pendulum: tan⁡θ=v2rg⇒v2=rgtan⁡θ\tan\theta = \frac{v^2}{rg} \Rightarrow v^2 = rg\tan\theta.
  2. v2=0.4×10×tan⁡45∘=4v^2 = 0.4 \times 10 \times \tan 45^\circ = 4
  3. v=2v = 2 m/s
  4. So the answer is (d) 2 m/s.
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