A constant force acts on two different masses independently and produces accelerations A₁ and A₂. When the same force acts on their combined mass, the acceleration produced is (a) A₁ - A₂ (b) A₁ + A₂ (c) (A₁A₂)/(A₁ + A₂) (d) √(A₁² + A₂²)

Answer: (c). F = m₁A₁ = m₂A₂ ⇒ m₁ = F/A₁, m₂ = F/A₂ a = (F)/(m₁ + m₂) = (F)/(F/A₁ + F/A₂) = (A₁A₂)/(A₁ + A₂) So the answer is (c) (A₁A₂)/(A₁ + A₂).

A constant force acts on two different masses independently and… | MHT CET 2025 (22 Apr, Shift 2)

Q5MHT CET 2025 · 22 APR · SHIFT 2Easy

Inertia, First & Second Laws

A constant force acts on two different masses independently and produces accelerations $A_1$ and $A_2$ . When the same force acts on their combined mass, the acceleration produced is

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Answer: (c)

$F = m_1A_1 = m_2A_2 \Rightarrow m_1 = \frac{F}{A_1},\ m_2 = \frac{F}{A_2}$
$a = \frac{F}{m_1 + m_2} = \frac{F}{F/A_1 + F/A_2} = \frac{A_1A_2}{A_1 + A_2}$
So the answer is (c) $\frac{A_1A_2}{A_1 + A_2}$ .

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Inertia, First & Second Laws question from MHT CET 2025 (22 Apr, Shift 2)

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