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JEE Main 2021 (18 Mar, Shift 1) · Power

Power question from JEE Main 2021 (18 Mar, Shift 1)

Q27JEE Main 2021 · 18 MAR · SHIFT 1Easy

Power

A constant power delivering machine has towed a box, which was initially at rest, along a horizontal straight line. The distance moved by the box in time 't' is proportional to :-

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Answer: (b)

  1. Constant power: mvdvdt=P⇒v∝t1/2mv\dfrac{dv}{dt} = P \Rightarrow v \propto t^{1/2}.
  2. s=∫0tv dt∝t3/2s = \int_0^t v\,dt \propto t^{3/2}
  3. So the answer is (b) t3/2t^{3/2}.
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