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NEET 2023 · Rotational Kinematics & Dynamics

Rotational Kinematics & Dynamics question from NEET 2023

Q23NEET 2023Easy

Rotational Kinematics & Dynamics

A constant torque of 100 N m100\text{ N m} turns a wheel of moment of inertia 300 kg m2300\text{ kg m}^{2} about an axis passing through its centre. Starting from rest, its angular velocity after 3 s3\text{ s} is :-

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Answer: (a)

  1. α=τI=100300=13\alpha = \frac{\tau}{I} = \frac{100}{300} = \frac{1}{3} rad/s2^2
  2. From rest: ω=αt=13×3=1\omega = \alpha t = \frac{1}{3} \times 3 = 1 rad/s
  3. So the answer is (a) 1 rad/s.
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