Kirchhoff's Laws & Measuring Instruments question from NEET 2025

Answer: (d)

1. $1\ \Omega \parallel 3\ \Omega = 0.75\ \Omega$ (between A-side and CD), $2\ \Omega \parallel 4\ \Omega = \frac{4}{3}\ \Omega$ (between CD and B-side).
2. $R = 0.75 + \frac{4}{3} = \frac{25}{12}\ \Omega$, $I = \frac{50 \times 12}{25} = 24\text{ A}$
3. First pair: $V = 24 \times 0.75 = 18\text{ V}$, so $I_{1\Omega} = 18\text{ A}$.
4. Second pair: $V = 24 \times \frac{4}{3} = 32\text{ V}$, so $I_{2\Omega} = 16\text{ A}$.
5. At C: $I_{CD} = 18 - 16 = 2\text{ A}$
6. So the answer is (d) 2.0 A.