A container is divided into two chambers by a partition. The volume… | JEE Main 2021 (26 Feb, Shift 1)

Q62JEE Main 2021 · 26 FEB · SHIFT 1Medium

Gas Laws & Ideal Gas Equation

A container is divided into two chambers by a partition. The volume of first chamber is 4.5 litre and second chamber is 5.5 litre. The first chamber contain 3.0 moles of gas at pressure 2.0 atm and second chamber contain 4.0 moles of gas at pressure 3.0 atm. After the partition is removed and the mixture attains equilibrium, then, the common equilibrium pressure existing in the mixture is x $\times$ 10 $-$ 1 atm. Value of x is ________.

Numerical answer type. Work it out, then open the answer.

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Answer: 25

Internal energy (and so $PV$ total) is conserved on mixing: $P(V_1 + V_2) = P_1V_1 + P_2V_2$ .
$P = \frac{2.0 \times 4.5 + 3.0 \times 5.5}{10} = \frac{9 + 16.5}{10} = 2.55$ atm.
$2.55\text{ atm} = 25.5 \times 10^{-1}$ atm, so $x \approx 25$ .

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