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MHT CET 2025 (19 Apr, Shift 2) · Spherical Surfaces & Thin Lenses

Spherical Surfaces & Thin Lenses question from MHT CET 2025 (19 Apr, Shift 2)

Q22MHT CET 2025 · 19 APR · SHIFT 2Easy

Spherical Surfaces & Thin Lenses

A convex lens of focal length 13 m\frac{1}{3}\text{ m} forms a real, inverted image twice the size of the object. The distance of the object from the lens is

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Answer: (a)

  1. Real image twice the size: v=f(1+m)=13(1+2)=1 mv = f(1 + m) = \frac{1}{3}(1 + 2) = 1\text{ m}
  2. Object distance ∣u∣=vm=12=0.5 m|u| = \frac{v}{m} = \frac{1}{2} = 0.5\text{ m}
  3. So the answer is (a) 0.5 m.
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