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JEE Main 2025 (8 Apr, Shift 2) · Combination of Lenses

Combination of Lenses question from JEE Main 2025 (8 Apr, Shift 2)

Q14JEE Main 2025 · 8 APR · SHIFT 2Medium

Combination of Lenses

A convex lens of focal length 30 cm is placed in contact with a concave lens of focal length 20 cm. An object is placed at 20 cm to the left of this lens system. The distance of the image from the lens in cm is ________.

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Answer: (b)

  1. 1F=130−120=−160\frac{1}{F} = \frac{1}{30} - \frac{1}{20} = -\frac{1}{60}
  2. u=−20u = -20: 1v=1F+1u=−160−120=−460\frac{1}{v} = \frac{1}{F} + \frac{1}{u} = -\frac{1}{60} - \frac{1}{20} = -\frac{4}{60}
  3. v=−15 cmv = -15\text{ cm} (virtual, on the object side).
  4. So the answer is (b) 15.
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