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MHT CET 2021 (20 Sep, Shift 2) · Spherical Surfaces & Thin Lenses

Spherical Surfaces & Thin Lenses question from MHT CET 2021 (20 Sep, Shift 2)

Q70MHT CET 2021 · 20 SEP · SHIFT 2Easy

Spherical Surfaces & Thin Lenses

A convex lens of focal length ff is used to form an image whose size is one fourth that of size of the object. Then the object distance is

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Answer: (b)

  1. A diminished image by a convex lens is real: u=−v1/4=−4vu = -\frac{v}{1/4} = -4v.
  2. 1v+14v=1f⇒v=5f4\frac{1}{v} + \frac{1}{4v} = \frac{1}{f} \Rightarrow v = \frac{5f}{4}
  3. ∣u∣=4v=5f|u| = 4v = 5f
  4. So the answer is (b) 5f.
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