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MHT CET 2026 (12 May, Shift 2) · Spherical Surfaces & Thin Lenses

Spherical Surfaces & Thin Lenses question from MHT CET 2026 (12 May, Shift 2)

Q2MHT CET 2026 · 12 MAY · SHIFT 2Easy

Spherical Surfaces & Thin Lenses

A convex lens of focal length FF produces a real image ′n′'n' times the size of the object. The image distance is

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Answer: (d)

  1. Real image: m=vu=−nm = \frac{v}{u} = -n, so u=−vnu = -\frac{v}{n}.
  2. Lens formula: 1v−1u=1F⇒1v+nv=1F\frac{1}{v} - \frac{1}{u} = \frac{1}{F} \Rightarrow \frac{1}{v} + \frac{n}{v} = \frac{1}{F}
  3. v=F(n+1)v = F(n + 1)
  4. So the answer is (d) F(n+1)F(n+1).
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