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MHT CET 2024 (4 May, Shift 2) · Spherical Surfaces & Thin Lenses

Spherical Surfaces & Thin Lenses question from MHT CET 2024 (4 May, Shift 2)

Q44MHT CET 2024 · 4 MAY · SHIFT 2Medium

Spherical Surfaces & Thin Lenses

A convex lens of refractive index 32\frac{3}{2} has a power 2.5. If it is placed in a liquid of refractive index 2, the new power of the lens is

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Answer: (d)

  1. PlPa=μμl−1μ−1=0.75−10.5=−12\frac{P_l}{P_a} = \frac{\frac{\mu}{\mu_l} - 1}{\mu - 1} = \frac{0.75 - 1}{0.5} = -\frac{1}{2}
  2. Pl=−12×2.5=−1.25P_l = -\frac{1}{2} \times 2.5 = -1.25 D
  3. So the answer is (d) −1.25-1.25 D.
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